The concentration of pb2+ in a commercially available standard solution is 1.00 mg/ml. what volume of this solution should be diluted to 6.0×102 ml to produce a solution in which the concentration of pb2+ is 0.054 mg/l?

The concentration of pb2+ = 1.00mg/ml Diluted Solution is 6.0 x 102 ml = 612 ml Volume of the concentration of pb2+ is 0.054 mg/l is v (vL)(1.00mg/ml) = (.612L)(0.054mg/l) Volume = 0.033048L Volume of the concentration of pb2+ is 0.054 mg/l = 33.048 ml.

Rn in the right answer