A20.0 % by mass solution of phosphoric acid (h3po4) in water has a density of 1.114 g/ml at 20°c. what is the molarity of this solution?

Molarity is 2.272M

Explanation:

The mass % of phosphoric acid is 20.0%

It means in 100 g of solution there is 20g of phosphoric acid in it.

Molarity = moles of solute dissolved per litre of solution.

So we need volume of solution

Volume can be calculated from mass and density as

Volume = mass / Density = 100/1.114 = 89.77 mL = 0.08977 L

Moles of solute = mass of solute / molar mass of solute

moles of solute = 20g / 98 = 0.204

molarity =

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.