Solid aluminum hydroxide reacts with a solution of hydrobromic acid. write a balanced molecular equation and a balanced net ionic equation, including the states of each species.

To find the balanced molecular equation, we need to find the symbols for each element and their charges and then balanced the equation. This comes out to: Al(OH)3(aq) + 3HBR(aq) ---> AlBr3(aq) + 3H2O(l) The net ionic equation is adding the charges and separating them into basic components. Al3+ + 3OH- + 3H+ + 3BR- --> Al3+ + 3Br + H3O+ We can cancel out the aluminum and bromine to get: 3OH-(aq) + 3H+(aq) --> 3H2O(l)

A balanced chemical equation is a description of chemical elements in the form of numbers and atoms. The reactants are shown on the left side while the right side depicts the products.

Solid aluminium hydroxide yields an acid-base effect with a solution of hydrobromic acid to produce aluminium bromide.The balanced molecular equation for aluminium hydroxide and hydrobromic acid can be written as:

       Al(OH)₃(aq) +  HBr(aq) ---> AlBr₃(aq) + H₂O(l)

It can be balanced as:

Bromide can be balanced by adding 3 as a coefficient in front of hydrobromic acid on the left side.

        Al(OH)₃(aq) + 3 HBr(aq) ---> AlBr₃(aq) + H₂O(l)

The hydrogen atom can be balanced by adding 3 as a coefficient in front of the water molecule on the right side of the reaction.

       Al(OH)₃(aq) + 3 HBr(aq) ---> AlBr₃(aq) + 3 H₂O(l)

Therefore, the balanced equation is:

       Al(OH)₃(aq) + 3 HBr(aq) ---> AlBr₃(aq) + 3 H₂O(l)

Next, the ionic equation can be written by adding the charges and separating the compounds in the basic form:

        Al³⁺ + 3 OH⁻ + 3H⁺ + 3 Br- --> Al³⁺ + 3 Br + H₃O⁺

Removing the aluminium and bromine ions from the reaction we will get:

      3 OH⁻(aq) + 3H⁺(aq) --> 3H₂O(l)

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