Chemistry, 12.07.2019 15:50 photon22

Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. if 100 grams of hydrochloric acid reacts with 100 grams of calcium, what is the limiting reactant? 2hcl + ca → cacl2 + h2

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Answer from: desiwill01

Answer is hydrochloric acid

Hope this helps!

Answer from: Turtlelover05

- The limiting reactant is HCl.

Explanation: The balanced equation is:

$2HCl+Ca\rightarrow CaCl_2+H_2$

It's a stoichiometry problem. Masses of both the reactants are given and the questions asks to find out the limiting reactant.

We convert the given grams of each reactant to moles on dividing by its molar mass. Now, we can calculate the moles of any of the product on multiplying the moles of the reactant by mole ratio.

We do this starting with both the reactants and see which one gives less number of moles of the product. The limiting reactant is the one giving least number of moles of the product.

Molar mass of HCl is 36.46 gram per mol and that of Ca is 40.08 gram per mol.

Let's say we calculate the moles of hydrogen gas produced in the reaction. Mole ratio of H_2 to HCl is 1:2 and the mole ratio of H_2 to Ca is 1:1 .

The calculations are as shown below:

$100gHCl(\frac{1molHCl}{36.46gHCl})(\frac{1molH_2}{2molHCl})$

= 1.37 mol [tex[H_2[/tex]

$100gCa(\frac{1molCa}{40.08gCa})(\frac{1molH_2}{1molCa})$

= 2.50 mol H_2

From above calculations, we get the least moles of hydrogen gas from 100 grams of HCl. So, the limiting reactant is HCl.

Answer from: Quest

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. if 100 grams of hydroch...

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