What is the final pressure (expressed in atm) of a 3.05 l system initially at 724 mm hg and 298 k, that is compressed to a final volume of 2.60 l at 273 k?

To answer this question, we will use the following equation:
(P1V1) / T1 = (P2V2) / T2 where:
P1 = 724 mm hg
V1 = 3.05 L
T1 = 298 K
P2 is the unknown we want to find
V2 = 2.6 L
T2 = 173 K

Substitute with the givens to calculate P2 as follows:
(724*3.05) / 298 = (P2*2.6) / 273
P2 = 778.057047 mm Hg = 1.023759 atm

Density because it’s holyyy