Calculate the frequency of the n = 6 line in the lyman series of hydrogen.

Lyman Series Working Formula:

1/λ = RH (1-(1/n^2))

Given:

n = 6
RH = Rydberg's constant = 1.0968x10^7 m^-1
c = speed of light = 3x10^8 m/s

Required: 

Frequency (Hertz or cycles per second)

Solution:

To solve for the wavelength λ, we substitute the given in the working formula
1/λ = RH (1-(1/n^2))
1/λ = 1.0968x10^7 m^-1 (1-(1/6^2))
λ = 0.0000000938 m or 93.8 nm 

To get the frequency, we will use the formula below. 
f = c/λ

We then substitute c or the speed of light,
f = (3x10^8 m/s) / 0.0000000938 m 

Therefore,
f = 3.2x10^15 s^-1

ANSWER: Frequency = 3.2x10^15 s^-1

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