You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final temperature of the water is 31.0°c. assuming no heat loss to the surroundings nor the calorimeter, calculate the heat capacity of the metal.

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

Cp = 1.36 J / g °C

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explanation:

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