Diethyl ether is produced from ethanol according to the following equation: 2ch3ch2oh(l) → ch3ch2och2ch3(l) + h2o(l) calculate the percent yield if 76.1 g of ethanol reacts to produce 22.1 g of ether.

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

1) molar ratios

2 moles CH3CH2OH : 1 mol CH3CH2OCH2CH3

3) convert 76.1 g of ethanol to number of moles

number of moles = mass in grams / molar mass

molar mass of CH3CH2OH = 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol = 46 g/mol

number of moles = 76.1 g / 46 g/mol = 1.654 mol

4) calculate theoretical yield: 

2 moles CH3CH2OH / 1 mol CH3CH2OCH2CH3 = 1.65 mol CH3CH2OH / x

=> x = 1.654 / 2 = 0.827 mol CH3CH2OCH2CH3

5) calculate the number of moles in 22.1g of ether

number of moles = mass in grams / molar mass

molar mass of ether = 4*12g/mol + 10*1 g/mol + 16g/mol = 74 g/mol

number of moles of ether = 22.1 g / 74 g/mol = 0.299 moles

6) Percent yield = [actual yield /  theoretical yield] * 100 = [0.299 / 0.827] * 100 = 36.15%

36.2%

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.

Sorry i dont understand the question can you rephase it?