How many grams of sodium chloride are present in a 0.75 m solution with a volume of 500.0 milliliters?

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219.375 g of NaCl is present in a 0.75 M solution with a volume of 500.0 milliliter

Explanation: -

Volume of NaCl solution = 500 mL

= 500/1000 = 0.5 L

Strength of NaCl solution = 0.75 M

Number of moles of NaCl = Strength of NaCl x Volume of NaCl

= 0.75 M x 0.5 L

= 3.75 mol

Molar mass of NaCl = 23 x 1 + 35.5 x 1

= 58.5 g / mol

Mass of NaCl = Molar mass x number of moles

= 58.5 g / mol x 3.75 mol

= 219.375 g

the answer is a

photosynthesis

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: