In plentiful air, 3.0 parts of carbon react with 8.0 parts of oxygen to form carbon dioxide. how much carbon is required to produce 2200 g of carbon dioxide?

600 g We've been told that 3.0 parts of carbon will react with 8.0 parts of oxygen. So let's use grams to say that 3.0 grams of carbon will react with 8.0 grams of oxygen to produce 11.0 grams of carbon dioxide (we get 11.0 grams of CO2 because of the law of conversation of mass. So 3.0 + 8.0 = 11.0). Now we want 2200 grams of CO2. So divide 2200 by 11 to get 200. The value 200 represents 1 part. Now multiply that by 3 (because we want to use 3 parts of carbon) and you'll get 200 * 3 = 600 grams of carbon to get 2200 grams of carbon dioxide.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !