Sodium hydrogen carbonate decomposes to produce sodium carbonate, carbon dioxide, and water by the following equation:
2 NaHCO38) Na2CO3(0) + CO2(9) + H20(2)
Which of the following statements is TRUE?
A. Two liters of sodium hydrogen carbonate decompose to form 1 liter of sodium carbonate, one liter of carbon
doixide, and one liter of water
B. One molecule of sodium hydrogen carbonate decompose to form one molecule of sodium carbonate, one
molecule of carbon doixide, and one molecule of water
C. Two moles of sodium hydrogen carbonate decompose to form one moles of sodium carbonate, one mole of
carbon doixide, and one mole of water
D. Two grams of sodium hydrogen carbonate decompose to form one gram of sodium carbonate, one gram of
carbon doixide, and one gram of water

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Catalysts and intermediateshope i