Calculate the standard free-energy changes for the following reactions at 25°c: (a) h2(g) + br2(l) → 2hbr(g)

a electronegativity decreases beacuse the size of nucleus is bigger.

idk what is it? is this a question that you know the answer or u dont

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.