When 55.8 g of Fe reacts with Cl2 according to the equation 2Fe + 3Cl2 --> 2FeCl3. How many moles of Cl2 are required to react with all the iron? 2.00 mol
1.00 mol
0.67 mol
1.50 mol

1.50 moles

Balanced equation:  2Fe + 3Cl₂ --> 2FeCl₃

find moles of iron:

moles = mass/Mr

moles = 55.8/56

moles = 0.9964 moles

use molar ratio:

2Fe : 3Cl₂

2 : 3

moles of Cl₂ = (0.9964/2)*3 = 1.50 moles

i believe it is c.) 1575 j.

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.