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Chemistry, 18.03.2022 19:40 quickestlearner5694

A stock solution is made by dissolving 66. 05 g of (NH4)2SO4 in enough water to make 250 mL of solution. A 10. 0 mL sample of this solution is then diluted to 50. 0 mL. Given that the molar mass of (NH4)2SO4 is 132. 1 g/mol, what is the concentration of the new solution? Use M subscript i V subscript i equals M subscript f V subscript f. And Molarity equals StartFraction moles of solute over liters of solution EndFraction. 0. 400 M 1. 60 M 5. 00 M 10. 0 M.

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