Write the double displacement reaction chemical equation of the highlight parts: - Copper (II) nitrate plus sodium carbonate solution and magnesium metal

- Copper (II) nitrate plus sodium carbonate solution and zinc metal

- Copper (II) nitrate plus sodium carbonate solution and copper metal

- zinc nitrate plus sodium carbonate solution and magnesium metal

- zinc nitrate plus sodium carbonate solution and zinc metal

- zinc nitrate plus sodium carbonate solution and copper metal

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2