Enter your answer in the provided box. Calculate the molarity of 6.14 g of LiNO3 in 505 mL of solution.

0.18

Explanation:

the molarity equation is moles of solute over L of solution:

mol (solute)/L (solution

so you need to convert 6.14g of LiNO3 into moles so:

6.14g LiNO3 • 1 mol

———— = 0.0890552 mol

68.946g LiNO3 (molar mass)

then you need to convert 505ml to L:

505/1000= 0.505

then you just follow the equation

0.0890552 mol / 0.505 L = 0.17634694 or 0.18 for sigfigs

0.18 M

hope this helps :)

your answer would be “dry”

the maximum mass of nh3 is nh3 in grams