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Chemistry, 16.02.2022 23:40 hwest98

50.0g of lead are placed in a calorimeter with 100.0mL of water. As a result the water's ΔT is 5.0℃ which calculates to 2100J of heat absorbed by water, what is the ΔH (change in heat) of the lead

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50.0g of lead are placed in a calorimeter with 100.0mL of water. As a result the water's ΔT is 5.0℃...
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