Determine the number of moles present in 32.5 g aluminum chloride.

0.244 moles

Explanation:

We know that if one mole of a substance is present, it has exactly the Avogadro number (NA) of particles.

NA=6.022×1023

Now, the mass of a sample can be given by the sum of the mass of all the particles in it.

So, we can say that the mass of one mole of a compound is equivalent to the mass of all the particles contained in one mole of a substance i.e., 6.022×1023 particles.

The mass of one mole of a substance is known as the molar mass of that substance. Its SI base unit is kg/mol but it is usually expressed in g/mol. It is a bulk property of a substance, not a molecular property.

Now, the molar mass of a sample is given by the mass of the sample substance divided by the number of moles of the substance present in the sample.

M=mn

So, the number of moles in a given sample can be given by

n=mM

Where n is the number of moles,

m is the mass of the substance given (in grams), and

M is the molar mass of the substance (in g/mol).

Now, the molecular mass of one mole of a compound is equal to the sum of atomic masses of all the elements present in the molecule.

So, the molecular mass of one mole of AlCl3 is

MAlCl3=MAl+3×MClMAlCl3=26.981+3×35.453MAlCl3=133.34g/mol

It is given to us that the mass of the sample substance is 32.5 grams.

So, the number of moles of the substance in the sample is

n=32.5g133.34g/moln≅0.244mol

Hence there are approximately 0.244 moles in a sample of 32.5 grams of aluminum chloride (AlCl3).

Note: It must be noted that in 2019, the SI base unit of molar mass was redefined. According to the new definition, the molar mass constant is

Mu=0.99999999965×10−3kg/mol

And not 1×10−3kg/mol.

But since the change is so insignificant, for practical purposes, the molar mass of an element is still considered to be equivalent to the atomic mass of the element.

they are both synthetic elements

explanation:

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