Calculate the volume of a carbon monoxide when 22 grams of CO(g) exerts a pressure of 99.5 Kpa at 50 C. The topic is Chemistry and is Ideal gas laws, please help

21.32 L

Explanation:

First, convert grams to moles using molar mass. C has a mass of 12 and O has a mass of 16. CO2 will therefore have a mass of 28 g/mol. Divide 22 by 28 to get about 0.79 moles. Convert C to Kelvin by adding 273; getting 323K. Then use the ideal gas law (PV=nRT) to solve for V (V=nRT/P). This gets you 21.32 L, hope this helps!

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

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