Based on the data given and a rate constant of 0.031 M−1⋅min−1, calculate the time at which the concentration of reactant A will be 0.150 M . t (min) [A]t(M)
0.00 0.500
20.0 0.382
40.0 0.310
60.0 0.260
80.0 0.224

Known :

[A]₀ = 0.500 M

[A] = 0.150 M

Based on units of rate constant :

k = 0.031 M⁻¹ · min⁻¹

We know it's a second order of reaction, so

1 / [A] = k • t + 1 / [A]₀

Plug in the value :

1 / (0.150) = 0.031 • t + 1 / (0.500)

t = 150.5 min

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explanation: