3.12 mol of S and 3.75 mol of O2 react according to the equation 2S (s) + 3O2 (g) → 2SO3 (g). Identify the limiting reactant. A) S

B) About 2

C) O

D) SO 3

O₂

Explanation:

2S(s) +3O₂(g) → 2SO₃(g)

The limiting reactant of a chemical reaction is one that we do not have enough of for the reaction to yield more products.

From the balanced equation above, the mole ratio of S to O₂ is 2 :3. This means that for every 2 moles of S, 3 moles of O₂ is needed.

Since we have 3.12 mol of S,

amount of O₂ needed

= (3.12 ÷2) ×3

= 4.68 mol

Since we only have 3.75 mol of O₂, O₂ is the limiting reactant.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.