1. Determine molarity
525 g of lead(II) nitrate, Pb(NO3)2, dissolved in 1250 mL of solu...
Chemistry, 14.01.2022 20:40 LuvIsRage2
1. Determine molarity
525 g of lead(II) nitrate, Pb(NO3)2, dissolved in 1250 mL of solution
Answers: 1
Chemistry, 22.06.2019 07:30
The scheme below is from a series of reactions that are part of a synthesis of vitamin a. answer the following questions with reference to this scheme. (i) what is "reagent a"? (ii) draw a step-by-step mechanism which explains the formation of compound c from compound b (iii) which reagents would you use to form compound e from compounds c and d (reagents b and c)? for each reagent suggested above in (ii) explain the role of the reagent in the reaction to (iv) form compound e. you may wish to do this by drawing a mechanism. 1. addition of reagent a но reagent a 2. н,о" thо oh нон-с compound a. compound b. compound c .ch-оh 1. reagent b "сно 2. reagent c сh oh compound e. compound d.
Answers: 2
Chemistry, 22.06.2019 19:00
Imagine that a new planet is discovered with two moons of equal mass: moon a and moon b. the mass of the new planet is greater than the combined mass of its moons. moon a is farther away from the new planet than moon b. what is the planet's gravitational pull on moon a compared to the planet's gravitational pull on moon b? the planet's gravity repels moon a with a greater force than it repels moon b, which is why moon a is farther away. the gravitational pull on moon b is greater than on moon a because moon b is closer to the new planet than moon a. the gravitational pull on moon b is greater than on moon a because moon b is farther away from the new planet than moon a. the gravitational pull on moon a is the same as the gravitational pull on moon b because distance does not affect the planet's gravity.
Answers: 1
Chemistry, 23.06.2019 00:00
The empirical formula of a compound is ch2o and its mass is 120 amu/molecule, what is its formula?
Answers: 1
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