How many grams of CaSO4 form when 50.0 mL of 0.20 M Ca(NO3)2 react with
excess potassium sulfate solution?
Ca(NO3)2 + K2SO4 → CaSO4 + 2KNO3
-
?] g CaSO4

Explanation:

.01 mol CaSO4 is the conversion factor between these values and now you just need to multiply it by the molar mass of .01 x 136.14=1.36g CaSO4

Apologies for having the wrong answer before this, it's been a long day.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

colorless gas, exhibiting a blue glow when placed in an electric field

b) solid

its a type of rock