If 65.8 grams of SO3 are produced in the unbalanced reaction below, how many grams of oxygen reacted? SO2(g) + O2(g) —> SO3(g) Show work please.

13.13g

Explanation:

65.8÷80.06 =0.821 mol the same

the same amount of moles of Oxygen reacts with

because the ratio is 1 :1-1

let's calculate how much grams for 0.821 of oxygen

oxygen 1 mole is =16 g

well for 0.821=16* 0.821 which is 13.136grams

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