Consider the balanced equation. PCl3 3H2O Right arrow. H3PO3 3HCl What is the percent yield of HCl if 42. 0 g of HCl are produced from the reaction of 62. 0 g of PCl3? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100. 28. 4% 72. 8% 85. 0% 93. 5%.

answer; /// i do believe that the correct answer is (a) boiling

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a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o