PLS HELP CHEM MIDTERM TOMORROW Different materials are used in X-ray tubes to produce X-rays for different applications. The table lists the frequencies of
different materials that might be used in an X-ray tube.
Material
Frequency (Hz)
Cobalt
1.67 x 1018
1.95 x 1018
Copper
Molybdenum
4.23 x 1017
What is the energy of photons given off in an X-ray tube that contains molybdenum, in units of 1 x 10-16)?

Thanks in advance !!

yes definetly because you are using energy

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.