A feed of 10,000 kg/h is 10 wt% acetic acid in water. The acetic acid will be removed using a solvent at 25 C. The raffinate will contain 1 wt% acetic acid. What solvent equilibrium ratio (also known as distribution coefficient), in mass fraction units, is required so that the solvent flow rate (kg/h) not exceed 5 times the feed

answer: mercury

explanation:

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

he would use the colour black