A chemist had a bottle of HCl (aq) of unknown concentration. She performed a titration experiment in order to determine its concentration. She pipetted 12.55 mL of the HCl solution into an Erlenmeyer flask. She then added about 21 mL of deionized water and 3 drops of phenolphthalein indicator dye to the flask. She titrated this mixture with 0.0716 M NaOH (aq), and obtained a permanent, pale pink endpoint after the addition of 23.16 mL of NaOH (aq). Calculate the molarity of the HCl solution and report your final answer with units and the correct significant digits.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2