Briefly explain which of the two solvent mixtures, 40% 2-propanol in water or 60% 2-propanol in water, is more polar.

the answer is definitely c.

2b2t

explanation:

2b2t

1 is the answer to this problem

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.