subject
Chemistry, 02.12.2021 21:50 tobywaffle1234

Calculate ,Volume, in L, of 3.4 mole sample of hydrogen gas at a pressure of 2.1 ATM at 23 °C. Please show step by step so I can comprehend all steps

ansver
Answers: 3

Another question on Chemistry

question
Chemistry, 22.06.2019 01:50
Ase your answer to this question on the information below.hydrocarbons and fissionable nuclei are among the sources used for the production of energy in the united states. a chemical reaction produces much less energy than a nuclear reaction per mole of reactant.the balanced chemical equation below represents the reaction of one molecule of a hydrocarbon with two molecules of oxygen.chemical equation: ch4 + 2o2 → co2 + 2h2o + 1.48 × 10−18 jthe nuclear equation below represents one of the many possible reactions for one fissionable nucleus. in this equation, x represents a missing product.nuclear equation: write an isotopic notation for the missing product represented by x in the nuclear equation.
Answers: 1
question
Chemistry, 22.06.2019 03:40
Can someone me with questions 12 and 13 plz.
Answers: 3
question
Chemistry, 22.06.2019 15:00
Phosphorous acid, h3po3(aq) , is a diprotic oxyacid that is an important compound in industry and agriculture. p k a1 p k a2 1.30 6.70 calculate the ph for each of the points in the titration of 50.0 ml of 1.5 m h3po3(aq) 1.5 m h 3 po 3 ( aq ) with 1.5 m koh(aq). 1.5 m koh ( aq ) .
Answers: 1
question
Chemistry, 23.06.2019 08:00
Can anyone answer these questions? ? i need it before 1: 00pm today
Answers: 3
You know the right answer?
Calculate ,Volume, in L, of 3.4 mole sample of hydrogen gas at a pressure of 2.1 ATM at 23 °C. Pleas...
Questions
question
Chemistry, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Chemistry, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
question
Mathematics, 20.10.2020 20:01
Questions on the website: 13722367