Chemical Equations Practice A. Balancing Equations
The following chemical equations have the proper reactants and products. Try to balance each using the
following steps:
1. Assemble the reactants out of the appropriate tiles.
2. Rearrange the reactants to form the products.
3. Figure out the number of each reactant and product required to make the equation balance and write the
numbers (the coefficients) in the boxes,
Fe
+
02
Fe 03
CHA
+
CO2
+
H2O
H2O
HCI
+
NaCl
+
02
NaOH
Cl2
H2O
Na
+
Naci
CO2
+
C6H12O6
+
02
anaing difficult equations

The correct answer is "hydrogen".

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.