A 2.37 g sample of a substance suspected of being pure gold is warmed to 71.8 ∘C and submerged into 15.9 g of water initially at 24.3 ∘C. The final temperature of the mixture is 27.0 ∘C.

specific heat capacity of the unknown is 629.66 J/kg C

Explanation:

As we know that gold is heated to 72.3 degree C and mixed with water at 24.8 degree C

Now the final temperature of the mixture is 26 degree C

here we can say that heat given by the gold = heat absorbed by the water

So we will have

Q_{in} = Q_{out}Q

in

=Q

out

2.62 s (72.3 - 24.8) = 15.6 (4186) (26 - 24.8)2.62s(72.3−24.8)=15.6(4186)(26−24.8)

so we will have

s = 629.66 J/kg Cs=629.66J/kgC

so specific heat capacity of the unknown is 629.66 J/kg C