1. What is the specific heat of a substance that requires 270 J of energy to raise the temperature of 4.2 grams by 25°C?

Heat required is mcΔT=100×0.39×50=1950 J

Solve any question of Thermodynamics with:-

Explanation:

This will require  

266.9

k

J

of heat energy.

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material,  

m

The temperature change that occurs,  

Δ

T

Once you have all that, this is the equation:

Q

=

m

×

c

×

Δ

T

(

Q

is usually used to symbolize that heat required in a case like this.)

For water, the value of  

c

is  

4.186

J

g

°

C

So,  

Q

=

750

×

4.186

×

85

=

266

858

J

=

266.858

k

J

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