An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 2 ml. The height of the water rose to 7 ml. If the mass of the stone was 25 g, what was its density?

The density of an object is the amount of mass per unit volume. The idea of putting the stone into the water in a graduated cylinder is that this tells you the volume of the stone. Since the water raised increased from the 2 mL mark to the 7 mL mark after putting it in the cylinder, the volume of the stone must be equal to 5 mL of water. At room temperature, 1 mL of water has the same volume as 1 cubic centimeter (cm^3), so the stone also has a volume of 5 cm^3.

To get the density, divide the mass of the stone by its volume:

D = m/v = (25 g)/(5 cm^3) = 5 g/cm^3

The density of the stone is 5 grams per cubic centimeter.

Hope this helps!

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)