Escribe la relacion entre las actividades humanas y el cambio climatológico ayud pli

English:

"Human activities contribute to climate change by causing changes in Earth's atmosphere in the amounts of greenhouse gas- es, aerosols (small particles), and cloudiness. The largest known contribution comes from the burning of fossil fuels, which releases carbon dioxide gas to the atmosphere." (ei.lehigh.edu)

Have a nice day!

  I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Español:

"Las actividades humanas contribuyen al cambio climático al provocar cambios en la atmósfera de la Tierra en las cantidades de gases de efecto invernadero, aerosoles (partículas pequeñas) y nubosidad. La mayor contribución conocida proviene de la quema de combustibles fósiles, que libera dióxido de carbono a la atmósfera." (ei.lehigh.edu)

¡Que tenga un lindo día!

  Espero que esto sea lo que estás buscando, pero si no, ¡comenta! Editaré y actualizaré mi respuesta en consecuencia. (ノ^∇^)

- Heather

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

you need to give more information