Fe + Cl2  Fe FeCl3 2. Al + O2 Al2O3
3. Fe3O4 + H2 Fe + H2O
4. P2O5 + H2O  H3PO4
5. Al(OH)3  Al2O3 + H2O
6.Ba(OH)2 + HCl  BaCl2 + H2O
7. Zn + Fe(NO3)3 Zn(NO3)2 + Fe
8. C3H6 + O2  CO2 + H2O
9.Ba(OH)2 + AlCl3  Al(OH)3 + BaCl2
10.Mg + Al2(SO4)3 MgSO4+ Al

a:

by the combination of an unlimited number of elements

explanation:

0.07 g/cm³

1.37 g/cm³

its pwirhfpiwe

explanation:

because dgjpwojefopjwp

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o