8) What mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride?

38.3 g

Explanation:

8) What mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride?

first write, then balance the equation

Fe + Cl2> FeCl3

2Fe + 3Cl2> 2FeCl3

2 moles of Fe require 3 moles of Cl2

the atomic mass of Fe is 56

20/56= 0.36 moles of Fe

this requires o.36 X 3/2 = 0.54 moles of Cl2

Cl2 has a molar mass of 35.5 X 2=71

1 mole of Cl2 is 71g

0.54 moles is 0.54 X 71 g= 38.3 g

a is the answer to this question

explanation:

0.88m hope i am correct : )