Calculate the cell potential, the equilibrium constant, and the free-energy change for: Ca(s)+Mn2+(aq)(1M)⇌Ca2+(aq)(1M)+Mn( s)
given the following Eo values:
Ca2+(aq)+2e−→Ca(s) Eo = -2.01 V
Mn2+(aq)+2e−→Mn(s) Eo = -1.23 V

Ca(s)+Mn2+(aq)(1M)⇌Ca2+(aq)(1M)+Mn(s)

Explanation:

possibly, yes.

explanation:

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< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >