. A car accelerates at a constant rate in a straight line. The velocity of the car increases from 4.9 m/s to 6.4 m/s in 3.00 minutes.
Calculate the acceleration of the car.
Give your answer to 3 significant figures.

The acceleration of the car is 0.0273.

Explanation:

We can find this by using the acceleration formula which is:

a = ( vf - vi ) / Δt

a is acceleration.

vi is the initial velocity.

vf is the final velocity.

When we substitute into the equation we get. . .

a = ( 6.4 - 4.9 ) / 3

and when we solve this equation we get 0.02734

Hope this helps. . . <3

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72