Please explain this and give answers

a) 2Ba + O2 → 2BaO

b) 2HCl + Mg → MgCl2 + H2

c) 2HCl + CuO → CuCl2 + H2O

d) Fe + O2 → Fe2O3

Explanation:

Okay so for

a), you must add 2 at the front of Ba and BaO bcuz you're gonna need your equation balanced.

like as you can see, O has 2 so yeahh, you've got to balance it nicely.

b) you must add 2 in front of HCl bcuz the Cl and H after the reaction happened has 2 in them, were talking about balancing so XD

c) and yes again, you're gonna have to add 2 in front of HCl bcuz of the same reason as b).

d) D is definitely a special case bcuz, Fe3+ with O2, so well if you do the cross multiplication technique you'll automatically get Fe2O3. Yas that's it.

English is not my first language so it's hella tuff to explain it to you from in much more detailed perspective T-T Sorry (´∩｡• ᵕ •｡∩`)

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

we need the questions , i may then you.