Given the following reaction: 2 C3H18 + 25 O2 → 16 CO2 + 18 H20 What is the percent yield when 41.43 g of CO2 are formed from the
reaction of 2.09 mole of C3H18 reacts with 2.22 mole of O2?

Answer(false);

Radon-222 or rn-222 has a half-life of 3.82 days. to determine the fraction of an original sample of rn-222 that remains unchanged after 7.646 days, we calculate the amount of rn-222 remaining after 7.646 days and divide it with the original amount. using 1 gram as a basis and using half-life calculation methods, we can determine that  0.249 or 0.25  grams of rn-222 will remain, and thus the fraction remaining is 0.25 or 1/4.

Answer/when the cell uses energy;