Please help I will mark brainlist - answer & explain how u did that
[ lesson : molarity ]

18) What is the molarity of a bleach solution containing 9.5 g of NaOCI per liter of bleach?

19) How much calcium hydroxide (Ca(OH)2) in grams, is needed to produce 1.5 L of a 0.25M solution

Q1) 0,1276 M

Molair mass of NaOCl = 74,44 g/mol

You have 9,5 g/L.

You need to calculate with the molar mass, how many moles 9,5 g are:

9,5 g / 74,44 g/mol = 0,1276 molAR

0,1276 mol / 1 L = 0,1276 M

Q2) 27.78  grams

The  mass    ca(Oh)2  needed  to  produce  1.5 l  of  0.25 solution  is  calculated  as follows

find  moles

=moles   = molarity   x  volume

moles is therefore =   1.5  x 0.25  =  0.375  moles

mass  =  moles  x  molar  mass

0.375mol  x  74.09 g/mol  =  27.78  grams

Explanation:

NOW MARK ME AS THE BRAINLIEST

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )