Pls help me with this!!1

Theoretical yield = 6.27

Percentage yield = 92%

Explanation:

2KOH + CO2 - K2CO3 + H2O

Theoretical yield =

Mr of 2KOH = 56g

5.09 / 56 = 0.09 moles of 2KOH

0.09 / 2 = 0.045 moles of K2CO3

Mr of K2CO3 = 138g

138 * 0.045 = 6.27

Percentage yield = 5.80/6.27 = 0.92

0.92 * 100 = 92%

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.