A sample containing 0.400 mol of a compound is composed of 2.41 × 1023 atoms of sodium, 14.19 g of chlorine atoms, and 19.22 g of oxygen atoms. The formula of the compound is A. NaCl2
B. NaClO
C. NaClO4
D. NaClO3
E. NaClO5

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally