Complete the table to show the relative charge of each particle and the number of each particle found in a 140 Ce2+ ion.
Particle
Relative charge of each particle Number of each particle present
in a 140 Ce2ion
proton
neutron
electron
1.0.1 58. 82. 60
O -1.0, +1 58. 82. 60
0-1.0. + 1 58, 82, 56
O +1, 0, -1 58, 82, 56

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

it is the most commonly accepted one

i'm wiling to try and you : )