An iron nail weighing 40.0 g is placed in 200.0 g of copper(II) sulfate, which reacts to form pure copper and iron(III) sulfate by the following reaction: __Fe(s) + __CuSO4(s) → __Fe2(SO4)3(s) + __Cu(s)
a. Fill in the missing coefficients to balance the equation.
b. What is the limiting reagent and the mass of iron(III) sulfate that is formed?
c. After the reaction goes to completion, what is the mass of the reactant that remains?

Fe(s) + CuSO4 (aq) ! FeSO4 (aq) + Cu(s)

Fe(s) + Cu+2(aq) ! Fe+2(aq) + Cu(s)

(2) 2Fe(s) + 3CuSO4 (aq) ! Fe2(SO4)3 (aq) + 3Cu(s)

2Fe(s) + 3Cu+2(aq) ! 2Fe+3(aq) + 3Cu(s)

Explanation:

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

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