Combustion of 1 mole of an organic compound requires 4 moles of oxygen. The formula of the organic compound is a) CH4 b) C2H c) C3H4 d) C2H4​

Ethanol (c2h5oh) is produced from the fermentation of sucrose in the presence of enzymes. c12h22o11(aq) + h2o(g) 4 c2h5oh(l) + 4 co2(g) determine the theoretical yield and the percent yields of ethanol if 680. g sucrose undergoes fermentation and 326.5 g ethanol is obtained. theoretical _ g _ percent %

Acompound has a molecular weight of 12.124 atomic mass units and the empirical formula c3h40. what is the molecular formula of the compound?

Chlorophyll a had the molecular formula c55h72mgn4o5 how many atoms are in this molecule