Chemistry, 02.09.2021 04:50 monkeys450

Cho hỗn hợp rắn X gồm KCl, MgCl2 và NH4Cl. Hòa tan 27,65 gam hỗn hợp X vào nước rồi cho tác dụng với dung dịch NaOH(dư) thì số mol NaOH phản ứng là 0,4 mol. Mặt khác, nếu hòa tan 0,6 mol hỗn hợp X vào nước rồi cho tác dụng với lượng dư dung dịch Na2CO3, thu được 12,6 gam kết tủa. Tính phần trăm khối lượng KCl có trong X.

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Cho hỗn hợp rắn X gồm KCl, MgCl2 và NH4Cl. Hòa tan 27,65 gam hỗn hợp X vào nước rồi cho tác dụng với...

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