500. ml of 1.00 M each of NiCl2 and NaOH react, how much Ni(OH)2 in g (92.7 g/mol) can you make? NiCl2 + 2NaOH → Ni(OH)2 + 2 NaCl

Your question is not clear but if you can explain yourself i would be glad to .  just trying to : ))

I'm sorry but i'm only grade

Electron equations of the given changes are as follow,a)                              cu      →      cu⁺²  + 2e⁻b)                              mg⁺²  +  2 e⁻      →      mgc)                              cl⁻    →      cl  +  1e⁻d)                              s  +  2 e⁻    →      s²⁻e)                                o²⁻      →      o  +  2 e⁻f)                              p  +  3 e⁻    →      p³⁻g)                              fe²⁺    →      fe³⁺  + 1 e⁻h)                              s²⁻    →      s⁴⁺  +  6 e⁻

The first one is the one that violate the law