Chemistry, 26.08.2021 15:40 photagraphykid
At a certain temperature the vapor pressure of pure heptane is measured to be .59 atm . Suppose a solution is prepared by mixing 85.9 of heptane and of acetyl bromide . Calculate the partial pressure of heptane vapor above this solution. Round your answer to significant digits. Note for advanced students: you may assume the solution is ideal.
Answers: 3
Chemistry, 21.06.2019 23:30
Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isÑťÃ‘ť=ћÑ›Ã‘›Ã‘›Ã‘›Ã‘›Ã‘‰Ã‘‰more accurate estimates can be made with the van der waals equationÑťÃ‘ť=ћÑ›Ã‘›Ã‘›Ã‘›Ã‘›Ã‘‰Ã‘‰â’ћÑ›Ã‘źÃ‘źâ’ўÑžÃ‘›Ã‘›2щщ2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?
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At a certain temperature the vapor pressure of pure heptane is measured to be .59 atm . Suppose a so...
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